Test functions, distributions, and Sobolev’s lemma
1 Introduction
If
The purpose of this note is to collect the material given in Walter Rudin, Functional Analysis, second ed., chapters 6 and 7, involved in stating and proving Sobolev’s lemma.
2 Test functions
Suppose that
where
For each compact
subset
and define
Define
We write
It is a fact that a linear functional
For
Let
which shows that
The Leibniz formula is the statement that
for all
where
For
this makes sense because
Lemma 1.
If
Proof.
Suppose that
For
Because
the last equality is how we define
This bound shows that
The above lemma shows that
Lemma 2.
If
If
For
from which it follows that
For
from which it follows that
If
Let
3 The Fourier transform
Let
Let
Using
and
For
The Fourier transform of
Using the dominated convergence theorem, one shows that
For
and let
The Riemann-Lebesgue lemma is the statement that if
The inversion theorem99
9
Walter Rudin, Functional Analysis,
second ed., p. 186, Theorem 7.7. is the statement that if
and that if
then
and hence that
and so
It is a fact that
there is some
4 Sobolev’s lemma
Suppose that
The following proof of Sobolev’s lemma follows Rudin.1212 12 Walter Rudin, Functional Analysis, second ed., p. 202, Theorem 7.25.
Theorem 3 (Sobolev’s lemma).
Suppose that
Suppose that
Proof.
To say that the distribution derivative
Suppose that
in particular, for
and using the Cauchy-Schwarz inequality,
Then,
(1) |
Because
hence, defining
we have
Let
and
Hence
and
It follows that
(2) |
Using (1), (2), and the inequality
we get
Let
This integral is finite if and only if
from which we get that
Define
(Note that
But
From the above expression, it is apparent that
For all